, it decelerates until it reaches its maximum height. At the peak of its trajectory, its instantaneous velocity is Set in the first equation: Maximum Height ( Hmaxcap H sub m a x end-sub ): Substitute tmaxt sub m a x end-sub into the position equation: 2. Visualize the Trajectory The graph below illustrates the position of an object thrown upward at
Choose whether "up" or "down" is the positive direction (usually up is positive, making negative). Identify initial conditions: Determine 1_Caduta_libera_Parte_2_
For an object returning to its starting height, the time spent rising equals the time spent falling, and the final impact speed equals the initial launch speed. Final Conclusion , it decelerates until it reaches its maximum height